11. Container With Most Water
You are given an integer array height
of length n
. There are n
vertical lines drawn such that the two endpoints of the ith
line are (i, 0)
and (i, height[i])
.
Find two lines that together with the x-axis form a container, such that the container contains the most water.
Return the maximum amount of water a container can store.
Notice that you may not slant the container.
Example 1:
Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
Example 2:
Input: height = [1,1]
Output: 1
Constraints:
n == height.length
2 <= n <= 105
0 <= height[i] <= 104
class Solution:
def maxArea(self, height: List[int]) -> int:
left, right = 0, len(height) - 1
maxVol = 0
curMax = 0
while left < right:
x_dist = right - left
if height[right] > height[left]:
curMax = height[left]*x_dist
# move the left pointer
left += 1
else:
curMax = height[right]*x_dist
right -= 1
maxVol = max(maxVol, curMax)
return maxVol